Question

a fighter aeroplane flys in the sky dives with a speed of 360 km/hr in a vertical cercle of radius 200m weight of the pilot sitting in it is 75kg what will be the value of force with which the pilot presses his seat when the aeroplane is at highest position

Answer 1

Method=1
At the top point :The pilot will experincemg downwards and Normal force also downwards.these both together will add upto give the reqired centifugal acceleration= mv2/rN + mg = mv2/rN =mv2/r−mg= mv2/r−mg= 75(1002 /200 − 10)= 3000 N

Method=2

convert speed into m/s

at the top of the circle Fc = T+mg

mv2/r = T + mg

T = mv2 /r - mg

= 75*1002 / 200 -75*10

T= 3000N

Only this much knowledge I have friend I solved problems of motion in vertical circle which involved string and stone. this is new to me but I am sure that this is the correct ans, I don't know what to write in place of T , if you know plz tell me also.

Answer 2

Hey mate ^_^

At the top point:

The pilot will experience mg downwards, 

Normal force also downwards.

These both together will add up to give the required centrifugal acceleration

= mv^2/rN + mg 

= mv^2/rN 

=mv^2/r−mg

= mv^2/r−mg

= 75(1002 /200 − 10)

= 3000 N


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