Physics, asked by anayaleslie8250, 9 months ago

A fighter plane is flying horizontally at a height of 500 m with a velocity of 150 metre per second. a bombe is released from it to strike a target
(i)time taken by the bomb to reach the target
(ii)the velocity with which the bomb hits the target (iii)the distance of the target . take g=10m/s

Answers

Answered by Anonymous
133

\huge\underline{\underline{\bf \orange{Question-}}}

A fighter plane is flying horizontally at a height of 500 m with a velocity of 150 metre per second. a bombe is released from it to strike a target

(i)time taken by the bomb to reach the target

(ii)the velocity with which the bomb hits the target (iii)the distance of the target . take g=10m/s

\huge\underline{\underline{\bf \orange{Solution-}}}

\large\underline{\underline{\sf Given:}}

  • Fighter plane is flying horizontally at height of ( H ) = 500m
  • It's moving with velocity ( v ) = 150m/s

\large\underline{\underline{\sf To\:Find:}}

  • Time taken by the bomb to reach the target
  • The distance of the target

Time Taken

\large{\boxed{\bf \blue{T = \sqrt{\dfrac{2H}{g}} }}}

\implies{\sf T=\sqrt{\dfrac{2×500}{10} }}

\implies{\sf T = \sqrt{100}}

\implies{\bf \red{Time\:taken(T)=10\sec}}

Distance Of The Target (R)

\large{\boxed{\bf \blue{ R = uT} }}

\implies{\sf R =  150×10 }

\implies{\bf \red{Range (R )= 1500\:m}}

\huge\underline{\underline{\bf \orange{Answer}}}

Time taken by the bomb to reach the target is {\bf \red{10\:sec}}

The distance of the target is {\bf \red{1500\:m}}

Answered by Anonymous
3

Time taken by the bomb to reach the target is {\bf \red{10\:sec}}

The distance of the target is {\bf \red{1500\:m}}

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