Question

A figure is in the form of a quadrilateral ABCD. Its area is 165 cm2 find the length
of the perpendicular drawn from Don AC if AC = 15 and length of perpendicular
from Bon AC is 12 cm.
​

Answer 1

$\Huge{\underline{\underline{\blue{\mathfrak{ Answer }}}}}$

$\\ \sf \hookrightarrow 10\ cm$

$\large \fbox{ \: \sf \blue{ Solution : - } \: \sf \underline}$

$\\ \sf {Area\ of\ quadrilateral = \frac{1}{2}\ d\ ( h_1 + h_2 )}$

$\sf 165\ cm^{2} = \frac{1}{2} \times 15\ (12 + d )$

$\sf 330 = 180 + 15d$

$\sf 15d = 150 = \frac{150}{15} = 10\ cm$

Answer 2

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