Question

A filament of an electric lamp draws a circuit of 0.4a which lights for 3 hours. calculate the amount of charge that flows through the circuit ?

Answer 1

current,I=0.4A
time,t=3h=3×60×60s=10800s
charge,Q=?
we know that
I=Q÷t
Q=it
Q=0.4a×10800s=4320c

Answer 2

Answer:

4320C.

Explanation:

Current in the electric lamp = I = 0.4A

Duration of the lamp = t = 3h = 3 × 60 × 60 s = 10800s

Charge in the lamp = Q=?

Average current = total charge flowing through the cross sectional area of wire/ the time taken to flow

Hence, the amount of charge flowing through the circuit -

I = Q/t

Q = It, hence -

= 0.4 × 10800

= 4320C

Thus, if a filament of an electric lamp draws a circuit of 0.4a which lights for 3 hours. then the amount of charge that flows through the circuit is 4320C.