Question

A fill the pipe in 16 and B fill in 10 and 3rd pipe pipe can empty 40 .all three pipes are open how man​

Answer 1

Answer:

The require time to fill the tank is $7\frac{3}{11}$ min.

Step-by-step explanation:

Pipe A fill the tank in 16 min.

∴In 1 min A fill the $\frac{1}{16}$ part of the tank.

Pipe B fill the tank in 10 min.

∴In 1 min B fill the $\frac{1}{10}$ part of the tank.

∴ In 1 min A and B can fill =$\frac{1}{16}+\frac{1}{10}$ part of the tank.

                                          =$\frac{5+8}{80}$ part of the tank.

                                          =$\frac{13}{80}$ part of the tank.

Pipe C can empty the tank in 40 min.

∴In 1 min Pipe C can empty $\frac{1}{40}$ part of the tank.

Now, If all the three pipes are open then,

In 1 min they fill = $\frac{13}{80}-\frac{1}{40}$ part of the tank.

                         = $\frac{13-2}{80}$ part of the tank.

                         = $\frac{11}{80}$ part of the tank.

∴ In $\frac{80}{11}$ min i.e. $7\frac{3}{11}$ min tank will be filled.

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