Question

A film of oil,refractive index 1.20,lies on water of refraction index 1.33,a light Ray is incidented at 30 degree in the oil water boundary.calculate the angle of refraction in the water

Answer 1

Dear Student,

◆ Answer -

r = 26.82°

● Explanation -

# Given -

n1 = 1.20

n2 = 1.33

i = 30°

r = ?

# Solution -

According to Snell's law -

n2/n1 = sini/sinr

1.33/1.2 = sin30/sinr

sinr = sin30 / (1.33/1.2)

sinr = 0.5 / 1.1083

sinr = 0.4511

Taking sin inverse,

r = arcsin(0.4511)

r = 26.82°

Hence, angle of refraction is 26.82°.

Thanks dear. Hope this helps you...