Question

A) Find the area of triangle formed by the line
xcosalpha+ ysinalpha =p with co-ordinate
axis.​

Answer 1

Answer:

Step-by-step explanation: xcosalpha+ ysinalpha =p

$\frac{x}{\frac{p}{cos\alpha } } +\frac{y}{\frac{p}{sin\alpha } }=1$

The x and y intercept are $\frac{p}{cos\alpha } ,\frac{p}{sin\alpha }$. So, area of triangle formed the given line is

$A=\frac{1}{2} (\frac{p}{cos\alpha })\frac{p}{sin\alpha }$

$A=\frac{p^{2} }{sin2\alpha }$