A. find the LCM of the following expressions.
Questions:
1. How did you get the lcm of the given?
2.What factoring techniques did you apply in item 2?
Answers
Answered by
0
Step-by-step explanation:
1. 12²y³ and 15x³y
2 x²-7x+6 and x²-1
1. 12²y³ = 3y×4×12× y²
15 x³y = 3y× 5x³
lcm = 3y ×4×12×y²×5x³ = 720 x³y³
2.x²-7x+6 = (x-1)(x-6)
x²-1 = (x+1)(x-1)
lcm = (x-1)(x-6)(x+1) = (x-6)(x²-1)
= x³-x-6x²+6=x³-6x²-x+6
Answered by
4
Solution :
Let's Split the Terms to prime factors
Lets have the Common terms once and left terms in product form
1. How did you get the LCM of the given ?
By splitting the terms into least prime factors and taking the common terms once and taking left terms as they were.
Solution :
So the LCM is
2. What factorising techniques you applied in terms 2 ?
For the first vale we applied quadratic equation technique and for the second value we have applied algebraic identity
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