A jar contains 4 green marbles, 2 brown marbles, and 1 gray marble. You draw one marble from the jar at random and without replacement, you draw a second marble. What is the probability of drawing a green marble and then a gray marble?
Answers
Answered by
2
Answer:
total number of marbles = 4+2+2= 8
probability of getting green marble is 4/8
probability of getting gray marble is 1/8
Step-by-step explanation:
Answered by
1
Step-by-step explanation:
Total number of marbles = 4+2+1 = 7
We know that,
P(E) = no of favourable outcomes/total number of outcomes
P(green marble) = 4/7
P(gray marble) = 1/7
Similar questions