Question

Find the value of k so that (x+1) is a factor of k^2x^2-2kx-3.

pls solve in detail
give right ans

Answer 1

Step-by-step explanation:

$x + 1 = 0 \\ x = - 1 \\ {k}^{2} {x}^{2} - 2kx - 3 = 0 \\ {k}^{2} {( - 1)}^{2} - 2k( - 1) - 3 = 0 \\ {k}^{2} + 2k - 3 = 0 \\ {k}^{2} + 3k - k - 3 = 0 \\ (k + 3)(k - 1) = 0 \\ k = 1$