Question

A fire broke out in the bazer. it broke out on Sunday last​

Answer 1

Answer:

I don't understand what are you asking

Answer 2

Answer:

$lhs = ( \sqrt{3} + 1)(3 - cot30) \\ = \sqrt[3]{3} - \sqrt{3} cot + 3 - 3cot30 \\ = \sqrt[3]{3} - \sqrt{3}cot30 + \sqrt{3} \sqrt{3} - \sqrt{3} \sqrt{3} - cot30 \\ = \sqrt[3]{3} - \sqrt{3} cot30(1 + \sqrt{3} ) + 3 \\= \sqrt[3]{3} - \frac{cot30}{tan30} (1 + \sqrt{3} ) + 3 \\= \sqrt[3]{ \]{3} } - \frac{cot30}{tan30} tan45 - \frac{cot30}{tan30 \: tan30} + {cot}^{2} 30 \\ = {tan}^{3} 60° - 2sin60° = rhs$

${\boxed {\boxed {⟹LHS=RHS}}}$