A fireman of mass 80 Kg slides down a pole during a rescue mission. The force of friction is constant at 720 N. Find the acceleration of the man. (g=10)
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Resultant force
= 800 - 720
= 80N
Hence
Force = Mass × Acceleration
80 = m × a
80 = 80a
a = 1 m/sec^2
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Answer:
answer is 1.0ms^-2
Explanation:
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