Question

A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:

Answer 1

first we will take the killed thing as Tiger

let the no of shot x,then
take the sum of A &B shots = 5+3= 8

 shot's fired by 1=shots upon total shots
 shot's fired by A=5/8x
 shot's fired by B= no of shots upon total shots
 shot's fired by B=3/8x
 killing shots by A = 1/3 of 5/8x=5/24x
 killing shots by B = 1/2 of 3/8x=3/16x
∴3/16 = 27 =x = 144
 Tiger killed by A = 5/24x = 5/24 × 144 = 30
∴ Tigers killed by A = 30.
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plzz mark as brainlist

Answer 2

Answer:

Explanation:

Refer the below attachment.