A fires 5 shots to B's 3 but A kills only
once in 3 shots while B kills once in 2
shots. When B has missed 27 times, A
has killed:
30
22
18
38.
Answers
Answered by
2
Answer:
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Answered by
3
Answer:
Let the no of shots be x. Then,
Shots fired by A =(5/8)x
Shots fired by B = (3/8)x
Killing shots by A = 1/3 of (5/8)x = (5/24)x
Shots missed by B = 1/2 of (3/8)x = (3/16)x
(3/16)x = 27 ⇒ x =144
Birds killed by A = (5/24)x = (5/24)*144 = 30
Answer = 30
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