Question

. A firetruck travelling at a speed of 30.0 m/s encounters an emergency and comes to a complete stop. How much time will it take for the car to stop if it decelerates at -4.0 m/s^2?

Answer 1

V = U + AT

0 m/s = 30m/s + (-4m/s^2) × T

0m/s = 30m/s - 4m/s^2 × T

- 30m/s = -4m/s^2T

-30/-4 =T

-15/-2 =T

7.5 seconds = T

Time taken to stop is 7.5 seconds