Question

A first order reaction has a rate constant 1.15 10−3 s−1. How long will 5 g of this reactant take to reduce to 3 g?

Answer 1

Hey Dear,

◆ Answer -

Time taken = 444 s

● Explaination -

# Given -

k = 1.15×10^-3 /s

Ao = 5 g

A = 3 g

# Solution -

Let t be the time taken for reactant concentration to change from 5 g to 3 g.

t = 2.303/k × log(Ao/A)

t = 2.303 / 1.15×10^-3 × log(5/3)

t = 2×10^3 × 0.2219

t = 443.8 s

Therefore, it will take approximately 444 s for reactant to become 444 s.

Thanks dear...

Answer 2

Answer:

.

t = 2.303/k × log(Ao/A)

t = 2×10^3 × 0.2219

t = 443.8 s