A first order reaction has a specific reaction rate of 10^ -2 per second . How much time will it take for 20 g of the reactant to reduce 5 grams?
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As we know
Half life of first order reaction = 0.693/k
Given
K=10¯²
T(half) =0.693/10¯²
T(half)=69.3 seconds
From 20grams first it will reduce to 10grams then 5 grams
So time will be in 2 steps
69.3 for first half part and 69.3 for second half
Time=69.3+69.3
=138.6 seconds
This is ur ans hope it will help you
Half life of first order reaction = 0.693/k
Given
K=10¯²
T(half) =0.693/10¯²
T(half)=69.3 seconds
From 20grams first it will reduce to 10grams then 5 grams
So time will be in 2 steps
69.3 for first half part and 69.3 for second half
Time=69.3+69.3
=138.6 seconds
This is ur ans hope it will help you
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Answer:
Half life of first order reaction = 0.693/k
Given
K=10¯²
T(half) =0.693/10¯²
T(half)=69.3 seconds
From 20grams first it will reduce to 10grams then 5 grams
So time will be in 2 steps
69.3 for first half part and 69.3 for second half
Time=69.3+69.3
=138.6 seconds
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