Question

A first order reaction is 50% completed in 30 minutes at 27ºC.
Its rate constant is :
(a) 2.31 × 10⁻² minute⁻¹ (b) 3.21 × 10⁻⁵ minute⁻¹
(c) 4.75 × 10⁻² minute⁻¹ (d) 1.33 × 10⁻³ minute⁻¹

Answer 1

The rate constant is k = 2.31 x 10^-2 min^-1

option (A) is correct.

Explanation:

For a first order reaction the relation between t(1/2) and rate constant is t(1/2)

t(1/2) = 0.693 / k

k = 0.693 / t(1/2)

k = 0.693 / 30

k = 0.231 / min

k = 2.31 x 10^-2 min^-1

Thus the rate constant is k = 2.31 x 10^-2 min^-1

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