Question

a first order reaction is found to have a rate constant K equals to 5.5 into 10 to the power minus 14 second inverse find the half life of the reaction ​

Answer 1

Explanation:

Half life of a first order reaction

$half \: life \: = \: \frac{ ln(2) }{k} \\ half \: life \: = \: \frac{ ln(2) }{5.5 \times {10}^{ - 14} } \\ half \: life \: = \: 1.2 \times {10}^{13} s$