Chemistry, asked by Mohammed1921, 9 months ago

A first order reaction takes 25 mins for 25% completion cculate t1/2

Answers

Answered by akshay23nagra
0

Answer:

t 1/2 = 60.26

Explanation:

Hope this help :)

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Answered by Thinkab13
0

Answer:

 \Large \bf{Given} -

t = 25min

25% of the reactants undergoes decomposition that means out of 100 particles in reactant 25 particles has been used

Now,75 particles will undergo out of 100 particles

 \Large \bf{To\:find} -

 \Large \sf{t_\frac{1}{2}} = \Large{?}

 \Large \bf{Answer}

 \text{You know for a first order reaction}  \text{half life is -}

 \Large \sf{t_\frac{1}{2}} =  \Large \frac{0.693}{k}

 \text{You can directly put half life formula }  \text{but k is missing}

 \text{So,now you have to bring k in order to }  \text{solve}

 \text{Now you can use,}

 \Large \sf{k} = \frac{2.303}{t} \log\frac{[R]_o}{[R]}

 \Large \sf{k} = \frac{2.303}{25} \log\frac{100}{75}

 \Large \sf{k} = \frac{2.303}{25} \log\frac{4}{3}

 \Large \sf{k} = \frac{2.303}{25} \log1.333

 \Large \sf{k} = \frac{2.303}{25}× 0.1249

 \Large \sf{k} = \frac{0.2876}{25}

 \large \sf{k} = 0.01150

 \text{Now put k in half-life formula}

 \Large \sf{t_\frac{1}{2}} = \frac{0.693}{0.01150}

 \Large \sf{t_\frac{1}{2}} = 60.26min

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