Chemistry, asked by aathrav8325, 1 year ago

A first order reaction takes 40min for 30% decomposition. Cal t1/2 for this reaction

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Answered by Yashika853649
1
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Answered by Thinkab13
0

 \Large \bf{Given} -

t = 40min

30% of the reactants undergoes decomposition that means out of 100 particles in reactant 30 particles has been used

Now,70 particles will undergo out of 100 particles

 \Large \bf{To\:find} -

 \large \sf{t_\frac{1}{2}} = ?

 \Large \bf{Answer}

 \text{You know for a first order reaction}  \text{half life is -}

 \Large \sf{t_\frac{1}{2}} =  \Large \frac{0.693}{k}

 \text{You can directly put half life formula }  \text{but k is missing}

 \text{So,now you have to bring k in order to }  \text{solve}

 \text{Now you can use,}

 \Large \sf{k} = \frac{2.303}{t} \log\frac{[R]_o}{[R]}

 \Large \sf{k} = \frac{2.303}{40} \log\frac{100}{70}

 \Large \sf{k} = \frac{2.303}{40} \log\frac{10}{7}

 \Large \sf{k} = \frac{2.303}{40} \log1.428

 \Large \sf{k} = \frac{2.303}{40}× 0.1548

 \Large \sf{k} = \frac{0.3565}{40}

 \Large \sf{k} = 0.008913

Now put k in half-life

 \Large \sf{t_\frac{1}{2}} = \frac{0.693}{0.008913}

 \Large \boxed \sf{t_\frac{1}{2}} = 77.75min

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