Physics, asked by yashkaranradcli26501, 11 months ago

A fish in the pond of a water appears at a depth of 6cm. What is the actual depth of the fish if refractive index of water is 4/3?

Answers

Answered by MidA
8

Solution:

actual depth = ref.Index × apparent depth

= 6 × 4/3

= 8 m........... answer...

hope, it helped you.

Answered by king2584
0

Answer:

8cm is the answer

Explanation:

hope it is helpfull

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