A fish in the pond of a water appears at a depth of 6cm. What is the actual depth of the fish if refractive index of water is 4/3?
Answers
Answered by
8
Solution:
actual depth = ref.Index × apparent depth
= 6 × 4/3
= 8 m........... answer...
hope, it helped you.
Answered by
0
Answer:
8cm is the answer
Explanation:
hope it is helpfull
Similar questions