Question

A fisherman lifts a fish of mass 250 g from rest through a vertical height of 1.8 m. The fish gains a speed of 1.1 m s1. What is the energy gained by the fish?

Answer 1

Dear Student,

◆ Answer -

Energy gained = 4.56125 J

● Explanation -

# Given -

m = 250 g = 0.25 kg

h = 1.8 m

v = 1.1 m/s

# Solution -

Energy gained by the fish is -

∆E = ∆PE + ∆KE

∆E = mgh + 1/2 mv²

∆E = 0.25 × 9.8 × 1.8 + 1/2 × 0.25 × 1.1²

∆E = 4.41 + 0.15125

∆E = 4.56125 J

Hence, gain in energy by fish is 4.56125 J.

Thanks dear. Hope this helps you...

Answer 2

Answer:

◆ Answer -

Energy gained = 4.56125 J

● Explanation -

# Given -

m = 250 g = 0.25 kg

h = 1.8 m

v = 1.1 m/s

# Solution -

Energy gained by the fish is -

∆E = ∆PE + ∆KE

∆E = mgh + 1/2 mv²

∆E = 0.25 × 9.8 × 1.8 + 1/2 × 0.25 × 1.1²

∆E = 4.41 + 0.15125

∆E = 4.56125 J

Hence, gain in energy by fish is 4.56125 J.