Question

A fixed mass of an ideal gas has a volume 800 cm cubeunder certain conditions. The pressure (in kPa) and temperature (inK) are both doubled . What is the volume of the gas after these changes with other conditions remaining the same? (a)200 cm cube (b)800 cm cube (c)1600 cm cube (d)3200 cm cube

Answer 1

1600 cm cube
is the right answer

Answer 2

Answer: The correct answer is 800 cm^3

Explanation:

So, let's use the combination of all gas laws:

P1V1/T1 = P2V2/T2

When we rearrange the above law, we get-

V2 = V1 X (P1/P2) X (T2/T1)

and P2 = 2 X P1 and T2 = 2 X T1

V2 = V1 X (P1/2P1) X (2T1/T1) = V1 X (1/2) X (2/1) = V1

Since we are getting V1 again, the volume of the gas does not change, which shows that the answer is 800 cm^3.

Hope this helps!