A fixed mass of gas occupies a volume of 273 cm3
at STP. At what pressure
the above gas will occupy a volume of 300 cm3
at 2 C ?
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Explanation:
STP is usually given as 273.15 K (0°C) and 1 atm.
formula
P1·V1/T1 = P2·V2/T2, where;
P1 = initial pressure = 1 atm
V1 = 27.3 cm^3
T1 = initial temperature 273.15 K
P2 = final pressure = ?
V2 = final temperature = 27.3 cm^3
T2 = 27°C + 273.15 = 300 K = 3.0×10^2 K to represent two significant figures
Rearrange the formula to isolate P2. Insert the known values and solve.
P2 = (P1·V1·T2)/(V2·T1)
P2 = (1 atm·27.3 cm^3·3.0×10^2 K)/(27.3 cm^3·273.15 K)
P2 = 1.1 atm
The pressure required is 1.1 atm.
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