Question

A fixed mass of gas occupies a volume of 273cmcube at S. T. P. At what pressure the above gas will occupy a volume of 300 cm cube at 7 degree Celsius. ​

Answer 1

Explanation:

STP is usually given as 273.15 K (0°C) and 1 atm.

The combined gas law can be used to answer this question. The formula is:

P1·V1/T1 = P2·V2/T2, where;

P1 = initial pressure = 1 atm

V1 = 27.3 cm^3

T1 = initial temperature 273.15 K

P2 = final pressure = ?

V2 = final temperature = 27.3 cm^3

T2 = 27°C + 273.15 = 300 K = 3.0×10^2 K to represent two significant figures

Rearrange the formula to isolate P2. Insert the known values and solve.

P2 = (P1·V1·T2)/(V2·T1)

P2 = (1 atm·27.3 cm^3·3.0×10^2 K)/(27.3 cm^3·273.15 K) = 1.1 atm to two significant figures

The pressure required is 1.1 atm.

Answer 2

the answer will be 0.91 .

Explanation:

P1 V1 = P2 V2