A fixed volume of a gas occupies 760 CM cube at 27 degree Celsius and 70 cm of HG. What will be its volume at S.T.P.
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V1 = 502 cm3
P1= 760 mm of Hg
T1= 273 K
T2=273+27 =300 K
P2= 720 mm
V2=?
Applying combined Gas Law :
P1V1/T1=P2V2/T2
(502*760)/273 = (720*V2)/300
V2 =582.30 cm3
P1= 760 mm of Hg
T1= 273 K
T2=273+27 =300 K
P2= 720 mm
V2=?
Applying combined Gas Law :
P1V1/T1=P2V2/T2
(502*760)/273 = (720*V2)/300
V2 =582.30 cm3
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