A flag pole 21m high casts a shadow 29m long. Then the distance of the top of the pole from the far end of the shadow is
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Given :-
A flag pole 21m high casts a shadow 29m long
To Find :-
The distance of the top of the pole from the far end of the shadow is
Solution :-
Let the distance of top of the pole to the shadow be x
Hypotenuse² = Base² + Perpendicula²
(x)² = (29)² + (21)²
x² = 841 - 441
x² = 400
x = √400
x = 20
Hence
Distance of the top of the pole from the far end of the shadow is 20 m
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Answered by
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In the question, it is given that :
- Height of the flag pole (h) = 21m
- Height of the shadow (s) = 29m
We have to find :
- The distance of the top of the pole from the far end of the shadow.
- Let's say that this distance is f.
The distance of the of the tip of the pole from the end of the shadow can be given by :
- Pythagoras theorem
- The distance is given by Pythagoras theorem because when we analyse the situation, we get a right angled triangle since the pole is perpendicular to the ground.
Here :
- Perpendicular : h = 21m
- Base : s = 29m
- Hypotenuse : f = x m
Substituting the values and finding the hypotenuse (x) :
- (B)² + (P)² = (H)²
- (29m)² + (21m)² = x²
- 841 + 441 = x²
- 1282 = x²
- √1282 = x
- x = 35.8 m
Therefore, the distance of the top of the pole from the far end of the shadow is 35.8m.
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