Question

A flag pole 21m high casts a shadow 29m long. Then the distance of the top of the pole from the far end of the shadow is​

Answer 1

Given :-

A flag pole 21m high casts a shadow 29m long

To Find :-

The distance of the top of the pole from the far end of the shadow is​

Solution :-

Let the distance of top of the pole to the shadow be x

Hypotenuse² = Base² + Perpendicula²

(x)² = (29)² + (21)²

x² = 841 - 441

x² = 400

x = √400

x = 20

Hence

Distance of the top of the pole from the far end of the shadow is​ 20 m

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Answer 2

In the question, it is given that :

• Height of the flag pole (h) = 21m
• Height of the shadow (s) = 29m

We have to find :

• The distance of the top of the pole from the far end of the shadow.
• Let's say that this distance is f.

The distance of the of the tip of the pole from the end of the shadow can be given by :

• Pythagoras theorem
• The distance is given by Pythagoras theorem because when we analyse the situation, we get a right angled triangle since the pole is perpendicular to the ground.

Here :

• Perpendicular : h = 21m
• Base : s = 29m
• Hypotenuse : f = x m

Substituting the values and finding the hypotenuse (x) :

• (B)² + (P)² = (H)²
• (29m)² + (21m)² = x²
• 841 + 441 = x²
• 1282 = x²
• √1282 = x
• x = 35.8 m

Therefore, the distance of the top of the pole from the far end of the shadow is 35.8m.