Question

A flask contains 0.34g of ammonia ( NH3). Calculate:
a) No of moles of NH;
b) No of molecules of NH3.
c) No of nitrogen and hydrogen atoms​

Answer 1

Answer:

(a) 0.02 moles.

$(b) \: 12.044 \times {10}^{21} \: \: \: \: molecules$

(c)

$nitrogen \: = 7.53 \times {10}^{20} \: atoms$

$hydrogen \: = 22.59 \times {10}^{20} \: \: atoms$

Explanation:

Refer to attachment...

Answer 2

Answer:

) 0.02 moles.

(b) \: 12.044 \times {10}^{21} \: \: \: \: molecules(b)12.044×10

21

molecules

(c)

nitrogen \: = 7.53 \times {10}^{20} \: atomsnitrogen=7.53×10

20

atoms

hydrogen \: = 22.59 \times {10}^{20} \: \: atomshydrogen=22.59×10

20

atoms

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