A flat Curve on a highway has radius of curvature 400 m.A car goes around the curve at a speed of 32 m/s.What is the minimum value of the coefficient of friction that will prevent the car from sliding?
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In order to prevent the vehicle from slipping away on a curve, the necessary centripetal force should be provided by the force of friction between the road and the wheels of the vehicle.
Force of friction=μmg ----- here μ is the coeficient of friction(which depends on the two interacting surfaces), m is the mass of the car and g is the gravitational acceleration.
Centripetal force =
r
m
V
2
both should be equal. So,
μmg=
r
m
V
2
μ=
rg
V
2
=
400×9.8
32
2
=0.261.
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