A flat plate of side 20 cm moves over another similar plate with a thin layer of 0.4 cm of a liquid between them. If a force of one kg wt. moves one of the plates uniformly with a
velocity of 1m/s, calculate the coefficient of viscosity.
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Answer:
η = 0.98 Pa sec
Explanation:
Given :
Side of plate = 20 cm
= > Area of plate = 20 × 20 = 400 cm²
Area in term of m² :
= > Area = 400 × 10⁻⁴ m²
Force = 1 kg wt = 9.8 N
d v = 1 m / sec
d x = 0.4 cm
We know :
η = F / A ( d v / d x )
η = 9.8 × ( 0.4 × 10⁻² ) / 400 × 10⁻⁴ × 1
= > η = 9.8 × ( 0.4 ) / 400 × 10⁻² × 1
= > η = 9.8 × ( 0.4 ) / 4
= > η = 0.98 Pa sec
Therefore , we get required answer.
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