Question

A floor 4.5 long and 3.6 m wide is to be covered with tiles. A 6 cm square tile costs ₹23.2. What will be the cost to cover the floor with three tiles

Answer 1

Explanation:

Length of the floor = 4.5 m = (4.5 × 100) cm = 450 cm Width of the floor – 3.6 m – (3.6 × 100) cm = 360 cm ∴ Area of the floor – (450 × 360) cm2 = 162000 cm2 Side of a square tile = 6 cm ∴ Area of one square tile = (6 × 6) cm2 = 36 cm2 Number of tiles required to cover the floor = Area of floor/ Area of one tile = 4500 Now, cost of one tile = ₹ 23.25 ∴ Cost of 4500 tiles =₹ (23.25 × 4500) = ₹ 10462