An examination is being held in two parts and there are 572 examinees in all. 3/11
of the total
number of examinees appears in part I only and3/11
to appears in part if only. The rest appear
in both the parts. Find the number of candidates appearing in both the parts.
Answers
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3
Answer:
260
Step-by-step explanation:
TOTAL EXAMINEES 572
3/11 OF 572 = 572÷11×3= 156 had taken part in first part
and 156 had taken in 2 part
no. of EXAMINEES taken in both = 572-156+156=
572-312=260 ans.
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