Question

A floor 8m 20cm by 6m is to be covered with tiles of size 20cm by 15cm.find the number of tiles required and the total cost of the tiles if the tiles come at Rs240 per 15 tiles

Answer 1

hi friend
here's your answer looking for
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area of floor =
$8m 20cm \times 6m \\ = 820cm \times 600cm \\ =492000 {cm}^{2}$
area of tile =
$20cm \times 15cm \\ = 300 {cm}^{2}$
number of tile required =
$\frac{492000}{300} \\ = 1640$
now , cost of each tile =
$\frac{240}{15} \\ = 16$
so, cost of 1640 tile =
$1640 \times 16 \\ = 26240$

sorry I had attached image by mistaken
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hope you are satisfied with my answer
from brainly benefactor
Amaytripathi19