A floor has a pattern where every 3rd tile has a black flower and every 4th file ho
flower. Find the first 4 positions of tiles that would have both black and white flowers
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Given : A floor has a pattern where every 3rd tile has a black flower and every 4th tile has white flower.
To Find : the first 4 positions of tiles that would have both black and white flowers
Solution:
Every 3rd tile = black flower
Every 4th tile has white flower
as 3 and 4 are co prime
Hence every 3 * 4 = 12th tile will have both black and white flowers
Hence 12th , 24th , 36th and 48th will be first 4 positions of tiles that would have both black and white flowers
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