A floor having length 6.5m and breath is 4.5m is laid by tiles of 13 cm length and 15cm. How many tiles are needed to cover the floor
Answers
Answered by
1
length of the floor=6.5m=650cm
breath of the floor=4.5m=450cm
area=650×450=292500cm^2
length of tiles=13cm
breath of tiles=15cm
area=13×15=195cm^2
the number of tiles required= 292500cm^2/195cm^2=1500
breath of the floor=4.5m=450cm
area=650×450=292500cm^2
length of tiles=13cm
breath of tiles=15cm
area=13×15=195cm^2
the number of tiles required= 292500cm^2/195cm^2=1500
Abprasnajitmund123:
is it right
or
not
Correct nice answer
thankx
Similar questions