Question

a floor is 4.5m long and 3.6m wide. a 6cm square tile costs ₹23.25.what will be the cost to cover the floor with these tiles

Answer 1

The area of the floor = The are of tiles to cover it
Now,
Area of floor = 450 * 360 cm² = 162000cm²
And, area of 1 tile = 6*6 = 36 cm²
No. of tiles to cover the floor = Area of floor / Area of 1 tile
i.e. 162000/36 = 4500
Hence, the no. of tiles to cover the floor will be 4500
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Answer 2

length(l)=4.5m=450cm
width(w)=3.6m=360cm

area of the floor(A)=l×w=162000cm²

area of tile=6cm²

tiles required for total floor=162000÷6=27000

Cost of one tile=Rs.23.25
then,cost of 27000 tiles=27000×23.25=Rs.627750