Math, asked by mahika39, 1 year ago

A floor is 40 m long and 15 m broad . It is covered with tiles , each measuring 60 cm by 50 cm . Find the number of tiles required to cover the floor.

Answers

Answered by SmãrtyMohït
21
Here is your solution

GIVEN:-

A floor is 40 m long and 15 m broad .

Covered with tiles , each measuring 60 cm by 50 cm.

Now

Area of floor= Lenght ×breadth =40×15=600m^2

Area of tiles =60×50=3000cm^2=30m^2

Now

Number of tiles required => area of floor/Area of 1 tiles

=>600m^2/30m^2=20

hence

Number of tiles required to cover the floor is 20

hope it helps you

mahika39: wrong ans.
mahika39: 2000
mahika39: i know it is in my book
mahika39: look for another ans.
mahika39: that is right
mahika39: no
Answered by hcarun
1

Answer:

Step-by-step explanation:

Given:

A floor is 40m by 15m

each tile is 60cm by 50 cm

Area of the floor = LxB = 40mx15m = 600 m²

Area of the tile = 60cm x 50cm = 3000cm²= 0.3 m²

Number of tiles required = Area of the floor / Area of a tile

= 600/0.3= 2000 tiles

2000 tiles are required

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