A floor is 40 m long and 15 m broad . It is covered with tiles , each measuring 60 cm by 50 cm . Find the number of tiles required to cover the floor.
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Answered by
21
Here is your solution
GIVEN:-
A floor is 40 m long and 15 m broad .
Covered with tiles , each measuring 60 cm by 50 cm.
Now
Area of floor= Lenght ×breadth =40×15=600m^2
Area of tiles =60×50=3000cm^2=30m^2
Now
Number of tiles required => area of floor/Area of 1 tiles
=>600m^2/30m^2=20
hence
Number of tiles required to cover the floor is 20
hope it helps you
GIVEN:-
A floor is 40 m long and 15 m broad .
Covered with tiles , each measuring 60 cm by 50 cm.
Now
Area of floor= Lenght ×breadth =40×15=600m^2
Area of tiles =60×50=3000cm^2=30m^2
Now
Number of tiles required => area of floor/Area of 1 tiles
=>600m^2/30m^2=20
hence
Number of tiles required to cover the floor is 20
hope it helps you
mahika39:
wrong ans.
Answered by
1
Answer:
Step-by-step explanation:
Given:
A floor is 40m by 15m
each tile is 60cm by 50 cm
Area of the floor = LxB = 40mx15m = 600 m²
Area of the tile = 60cm x 50cm = 3000cm²= 0.3 m²
Number of tiles required = Area of the floor / Area of a tile
= 600/0.3= 2000 tiles
2000 tiles are required
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