Question

a floor of a room is of dimensions4m ×6 cm. tiles of size 10cm×12cm have to lay on it .how many titles are required to cover the floor completely

Answer 1

$\bf{Heya \: mate \:. Solution \:below.}$
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★ For room,

length (l) = 4 m = 400 cm

breadth (b) = 6 m = 600 cm



=>>> Area of room,

= l × b

= 400 cm × 600 cm

= 240000 cm²




★ For 1 tile,

l = 10 cm

b = 12 cm



=>>> Area of 1 tile,

= l × b

= 10 cm × 12 cm

= 120 cm²




★ Now, number of tiles required,


$= \frac{area \: of \: room}{area \: of \: 1 \: tile}$


$= \frac{240000}{120}$


$= 2000$



$\tiny{\boxed{Therefore, number\: of \:tiles\: required\: =\: 2000 \:tiles}}$
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$<marquee>Thank you.. ^_^$