Question

A floor tile has the shape of a parallelogram whose base is 48 cm and altitude is 20cm.how many such tiles are required to cover the floor of are 960m

Answer 1

$\underline{\textbf{Question :-}}$

A floor tile has the shape of a parallelogram whose base is 48 cm and altitude is 20 cm . How many such tiles are required to cover the floor of area $960m^2$ ?

$\underline{\textbf{Answer :-}}$

Given ,

Base of the parallelogram = 48 cm .

Altitude of the parallelogram = 20 cm .

Therefore ,

$Area = Base \times Height$

$= 48 \times 20 = 960 \: cm$

Also , given that the area of the floor = 960 metre = 96000 cm .

Therefore ,

Number of tiles required to cover the floor

$= \frac{96000}{960}$

$= 100$

Answer 2

Solution :

Given a || gm with -

Base = 48 cm

Altitude or Height = 20 cm

We know that :-

Area of || gm = Base × Height

=> ( 48 × 20 )cm = 960 cm.

Given , that the area of the floor = 960 m i.e. 96000 cm ( since 1 m = 100 cm )

So ,

$Total \: number \: of \: tiles \: required \: = \frac{Area \: of \: the \: given \: floor}{Area \: of \: the \: given \: parallelogram \:}$

$= > \frac{96000}{9 60} = 100$

Hence ,

The number of tiles required is 100.