Question

a floor tile has the shape of a right angle triangle whose hypotenuse is 10 cm and one of the side is 6 cm.how many such tiles are required to cover a floor area 1216 m square

Answer 1

Hey friend!!!

Here's ur answer...

___________

Hypotenuse = 10 cm
One side = 6 cm

So, other side =
$\sqrt{ {(10)}^{2} - {6}^{2} } \\ = \sqrt{100 - 36} \\ = \sqrt{64} \\ = 8cm$
So, area of tile =
$\frac{1}{2} bh \\ = \frac{1}{2} \times 8 \times 6 \\ = 24 {cm}^{2}$

Area of floor = 1296m² = 12960000 cm²


Number of tiles =
$\frac{area \: of \: floor}{area \: of \: tile} \\ = \frac{12960000}{24} \\ = 540000 \: tiles$
________


Hope it may help you...

Thank you :) ))