Question

A floor which measures 15m*8m is to be laid with tiles measuring 50cm by 25 cm . find the number tiles required. Further if a carpet is laid on the floor so that a space of 1m exists between its edges and the edges of the floor what fraction of the floor is uncovered

Answer 1

Breadth = 8 centimeter
length = 15 metre
Area = 15*8=120 m^2 or 1200000 cm^2
Measure of the tile = 50*25
Area = 1250cm ^2
No of tiles = 1200000/1250=960 tiles

Area of the floor is 120m ^3
Length of the carpet will be 2 m less than the length of the floor =13m
Breadth= 8-2 = 6 m
Area = 6*13=78m^2
Floor uncovered = 120m^-78sq m
=42 sq m
Fraction =42/120 or 7/20

Answer 2

Area of the floor = 15m × 8m

= 120m²

Length of one tile = 50cm to m

= 50/100 = 0.5m

Breadth of one tile = 25cm to m

= 25/100 = 0.25m

Area of one tile = 0.5×0.25

= 0.125m²

Therefore,

No.of tiles = Area of the floor / Area of one tile

= 120/0.125

= 960 tiles ..... Answer

Next,

Space = 1m

For both sides = 1×2m = 2m

Area of carpet = (15-2) (8-2)

= 13×6

= 78m²

Uncovered area = 120m² - 78m²

= 42m²

Therefore,

Fraction = 42/120

= 7/20 m...... Answer

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