Question

A flooring tile has a shape of parallelogram whose base is 18 cm and the corresponding
height is 6 cm. How many such tiles are required to cover a floor of area 540 m ?
af required you can split the tiles in whatever way you want to fill up the comers).​

Answer 1

Let us calculate the area of the floor tile first of all.

Since we know that the area of a parallelogram of base length 'b' and corresponding height 'h' is = bh

Area of given parallelogram = 6×18 = 108 cm²

The total area of the floor is given in the question as 540 m²

We need to make the units same.

1 m² = 1m × 1m = 100cm×100cm = 10000 cm²

So the area of the floor is 5400000 cm²

So the number of tiles required is = $\frac{5400000}{108}$ = 50,000

Hence exactly 50,000 tiles are required to cover the floor.

Answer 2

Base of the parallelogram-shaped flooring tile = 18 cm and its height = 6 cm

So,

Area of one tile = Base × Height

= 18 × 6

= 108 cm2

We have the area of floor = 540 m2

Hence, number of tiles = Total area/ Area of one tile

= (540 x 100 x 100)/108 [As, 1 m2 = (100 x 100) cm2]

= 50000