Math, asked by nargis8271, 1 year ago

a flooring tile has a shape of parallelogram whose base is 24 cm and the corresponding hieght is 10 cm. How many such tiles are required to cover a floor of area 1080 m2 (square) ?(If required you can split the tiles in whatever way you want to fill up the corners ).

Answers

Answered by shubhgupta1
9
area of parallelogram= base×height
2.4×0.1
=0.24m2
area of 1 tile=0.24m2
area of floor given=1080m2
number of tiles=area of floor÷area of 1 tile
number of tiles=1080÷0.24
number of tiles=45000
Answered by Anonymous
1

Answer:

45000 tiles are required to cover the floor.

Step-by-step explanation:

Given: Base of flooring tile = 24 cm = 24/100 m = 0.24 m

Corresponding height of a flooring tile = 10 cm = 19/100 m = 0.10 m

Now Area of flooring tile = Base * Altitude = 0.24 * 0.10 = 0.024 m^2

Number of tiles required to cover the floor = Area of floor/Area of one tile

                                                                             = 1080/0.024

                                                                             = (1080 * 1000)/24

                                                                             = 45 * 1000

                                                                             = 45000 tiles

Hence 45000 tiles are required to cover the floor.

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