Question

A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm . How many such tiles are required to cover a floor of area 1080m2 ?

Answer 1

please find the solution if any query then ask me

Answer 2

base=24cm
height =10cm

AREA OF PARALLELOGRAM(tile)=
base×height
=24×10
=240sq.cm
=2.4sq.m
$no. \:of \: tiles = \frac{area \: of \: floor}{area \: of \: tile}$

$no. \: of \: tiles = \frac{1080}{2.4}$

$no. \: of \: tiles = \frac{1080 \times 10}{24}$

$no. \: of \: tiles = \frac{10800}{24}$
we get,


$no. \: of \: \: tiles = 450$

Therefore,
the no. of tiles required to cover the floor is 450.

$hope \: this \: helps$