Question

A flooring tile has the shape of a rhombus whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 m2? ​

Answer 1

Answer:

Step-by-step explanation:

Given,

Base of Rhombus, b = 24 cm

Height of Rhombus, h = 10 cm

To Find,

Number are tiles required to cover a floor of area 1080 m².

Formula to be used,

Area of Rhombus = b × h

Solution,

Area of Rhombus = b × h

Area of Rhombus = 24 × 10

Area of Rhombus = 240 cm².

Here, Rhombus is given in cm².

And the total floor area is m²

10000 cm²  = 1 m²

Number of tiles to cover the floor area = 1080 × 10000/240

Number of tiles to cover the floor area = 45000

Hence, the Number of tiles to cover the floor area is 45000.

Answer 2

Answer:

Given :-

• A flooring tile has the shape of a rhombus whose base is 24 cm and the corresponding height is 10 cm.

To Find :-

• How much such tiles are required to cover a floor of area 1080 m².

Solution :-

Given :

• Length = 24 cm
• Breadth = 10 cm

We know that,

◆ Area of Rhombus = Breadth × Height ◆

According to the question by using the formula we get,

⇒ 24 cm × 10 cm

➠ 240 cm²

Area of floor = 1080 m²

We know that,

↦ 1 m = 100 cm

↦ 1 m² = 100 × 100 cm²

Hence, the area of floor,

➟ 1080 × 100 × 100

➥ 10800000 cm²

Now, we have to find the number of tiles,

We know that,

✦ Num of tiles = Area of floor ÷ Area of Rhombus ✦

⇒ 10800000 ÷ 240

➠ 45000 tiles

∴ The number of tiles required to cover a floor of area 1080 m² is 45000 tiles .