Question

A flooring tile has the shape of parallelogram whose base is 24 cm and corresponding height is 10 cm . How many such tiles are required to cover a floor of 1080 m²? ( if required you can split the tiles in whatever way you want to fill up the corners)​

Answer 1

Given,

Base of a flooring tile is 24 cm =0.24 m

Corresponding hight of a flooring tile =10 cm =0.10 m

Now, area of the flooring tile,

Base×Altitude

=0.25×0.10

=0.024

So,area of the flooring tile is 0.024 m².

Number of tiles required to cover the area,

Area of the floor/Area of one tile

=1080/0.024

=45000 tiles

Hence, 45000 tiles are required to cover the floor.

Answer 2

Question ::-

A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 ${m}^{2}$? (If required you can split the tiles in whatever way you want to fill up the corners.

Given ::-

• Flooring tile has parallelogram shape.

• Base = 24cm

• Height = 10cm

• Area of floor = 1080 ${m}^{2}$

To find ::-

• How much tiles are required ?

Solution ::-

Area of the floor

= 1080 ${m}^{2}$

= 1080 × 10000 ${cm}^{2}$

= 10800000 cm2 [∵ 1 m2 = 10000 ${cm}^{2}$ ]

_______

Area of 1 tile

= 1 × base × height

= 1 × 24 × 10

= 240 ${cm}^{2}$

___________

Number of tiles required

= $\dfrac{ Area\:of\:floor}{Area\:of\:1\:tile}$

= $\dfrac{10800000}{240}$

= 45000 tiles

Hence, 45000 tiles are required