Math, asked by aryan655, 1 year ago

a flooring tile is in the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm how many such tiles are required to cover a floor of area 1080 metres square

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Answers

Answered by Dsnyder
3
Given : base= 24 cm
Height= 20 cm
Area of floor= 1080 m²= 1080×100×100cm²
[1m²= 10000cm²]
 Area of the Parallelogram = base x height

= 24 x 10 = 240 cm²
Area of  1 tile = 240 cm²
[Tiles are in the shape of a parallelogram]

  Number of tiles required= Area of the Floor/Area of the Tiles

= 1080 X100 X100/240  =45000
Number of tiles required to cover a Floor= 45000

Answered by 0tohero
2
HERE IS YOUR ANSWER

Given: Base of flooring tile = 24cm = 0.24m

Corresponding height of a flooring tile = 10cm = 0.10m

Now,Area of flooring tile

= Base*Altitude

= 0.24*0.10

= 0.024m^2

Number of tiles required to cover the floor

= Area of floor/Area of one tile

= 1080/0.024

= 45000 tiles

Hence,45000 tiles are required to cover the floor.

HOPES THIS HELPS.....
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