a flooring tile is in the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm how many such tiles are required to cover a floor of area 1080 metres square
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Given : base= 24 cm
Height= 20 cm
Area of floor= 1080 m²= 1080×100×100cm²
[1m²= 10000cm²]
Area of the Parallelogram = base x height
= 24 x 10 = 240 cm²
Area of 1 tile = 240 cm²
[Tiles are in the shape of a parallelogram]
Number of tiles required= Area of the Floor/Area of the Tiles
= 1080 X100 X100/240 =45000
Number of tiles required to cover a Floor= 45000
Height= 20 cm
Area of floor= 1080 m²= 1080×100×100cm²
[1m²= 10000cm²]
Area of the Parallelogram = base x height
= 24 x 10 = 240 cm²
Area of 1 tile = 240 cm²
[Tiles are in the shape of a parallelogram]
Number of tiles required= Area of the Floor/Area of the Tiles
= 1080 X100 X100/240 =45000
Number of tiles required to cover a Floor= 45000
Answered by
2
HERE IS YOUR ANSWER
Given: Base of flooring tile = 24cm = 0.24m
Corresponding height of a flooring tile = 10cm = 0.10m
Now,Area of flooring tile
= Base*Altitude
= 0.24*0.10
= 0.024m^2
Number of tiles required to cover the floor
= Area of floor/Area of one tile
= 1080/0.024
= 45000 tiles
Hence,45000 tiles are required to cover the floor.
HOPES THIS HELPS.....
Given: Base of flooring tile = 24cm = 0.24m
Corresponding height of a flooring tile = 10cm = 0.10m
Now,Area of flooring tile
= Base*Altitude
= 0.24*0.10
= 0.024m^2
Number of tiles required to cover the floor
= Area of floor/Area of one tile
= 1080/0.024
= 45000 tiles
Hence,45000 tiles are required to cover the floor.
HOPES THIS HELPS.....
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