A flooring tiles has the parallelogram shape whose base is 24cm and height is 10cm. How many such tiles are required to cover a floor of area 1080m²?
Answers
Answered by
4
Answer:
Answer=45000 tiles
Step-by-step explanation:
First take out the area of one parallelogram tile by area of parallelogram that is base multiplied by height
That is, 24*10=240cm
Now, as you know that
1m=100cm and 1cm=1/100m
Therefore,240cm=240/100=2.4m
Now total area of the floor =1080m ^2
Therefore total no of tiles required = total area of the floor /area of one tile
That is 1080m^2/2.4m=45000
Answer=45000 tiles
Answered by
6
Answer:
Area of parallelogram = b × h
= 24 × 10
= 240cm²
1080m²= 108000cm²
no. of tiles = 108000
240
= 450
4.5 tiles are required to cover a floor of area 1080m²
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