In triangle ABC, angle B = 90°, AB = 7 cm and AC - BC = 1 cm. Find the values of sinA
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ac - bc = 1
ac = bc + 1
ac² = bc²+ ab²
(bc + 1)² = bc² + 49
bc² + 1 + 2bc = bc² + 49
2bc + 1 = 49
2bc = 48
bc = 24
∴sin c = ac/ab = 24 + 1 / 7 = 25 / 7
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