Math, asked by yashrathore6930, 10 months ago

In triangle ABC, angle B = 90°, AB = 7 cm and AC - BC = 1 cm. Find the values of sinA

Answers

Answered by Anonymous

2

ac - bc = 1

ac = bc + 1

ac² = bc²+ ab²

(bc + 1)² = bc² + 49

bc² + 1 + 2bc = bc² + 49

2bc + 1 = 49

2bc = 48

bc = 24

∴sin c = ac/ab = 24 + 1 / 7 = 25 / 7

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